apple_platform

Report an issue View source Nightly · 8.0 · 7.4 · 7.3 · 7.2 · 7.1 · 7.0 · 6.5

Corresponds to Xcode's notion of a platform as would be found in Xcode.app/Contents/Developer/Platforms. Each platform represents an Apple platform type (such as iOS or tvOS) combined with one or more related CPU architectures. For example, the iOS simulator platform supports x86_64 and i386 architectures.

Specific instances of this type can be retrieved from the fields of the apple_common.platform struct:

  • apple_common.platform.ios_device
  • apple_common.platform.ios_simulator
  • apple_common.platform.macos
  • apple_common.platform.tvos_device
  • apple_common.platform.tvos_simulator
  • apple_common.platform.watchos_device
  • apple_common.platform.watchos_simulator

More commonly, however, the apple configuration fragment has fields/methods that allow rules to determine the platform for which a target is being built.

Example:

p = apple_common.platform.ios_device
print(p.name_in_plist)  # 'iPhoneOS'

Members

is_device

bool apple_platform.is_device

Returns True if this platform is a device platform or False if it is a simulator platform.

name_in_plist

string apple_platform.name_in_plist

The name of the platform as it appears in the CFBundleSupportedPlatforms entry of an Info.plist file and in Xcode's platforms directory, without the extension (for example, iPhoneOS or iPhoneSimulator).
This name, when converted to lowercase (e.g., iphoneos, iphonesimulator), can be passed to Xcode's command-line tools like ibtool and actool when they expect a platform name.

platform_type

apple_platform_type apple_platform.platform_type

Returns the platform type of this platform.